360=15x+0x^2

Solution for 360=15x+0x^2 equation:

360=15x+0x^2

We move all terms to the left:

360-(15x+0x^2)=0

We get rid of parentheses

-0x^2-15x+360=0

We add all the numbers together, and all the variables

-1x^2-15x+360=0

a = -1; b = -15; c = +360;
Δ = b2-4ac
Δ = -152-4·(-1)·360
Δ = 1665
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1665}=\sqrt{9*185}=\sqrt{9}*\sqrt{185}=3\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-3\sqrt{185}}{2*-1}=\frac{15-3\sqrt{185}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+3\sqrt{185}}{2*-1}=\frac{15+3\sqrt{185}}{-2}
$